Conservation of mass in chemical reactions

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Conservation of mass in chemical reactions

Conservation of mass in chemical reactions

John Kitchin

Atoms cannot be destroyed in non-nuclear chemical reactions, hence it follows that the same number of atoms entering a reactor must also leave the reactor. The atoms may leave the reactor in a different molecular configuration due to the reaction, but the total mass leaving the reactor must be the same. Here we look at a few ways to show this.

Contents

Water gas shift reaction

We consider the water gas shift reaction : % $CO + H_2O \rightleftharpoons H_2 + CO_2$. We can illustrate the conservation of mass with the following equation: $\bf{\nu}\bf{M}=\bf{0}$. Where $\bf{\nu}$ is the stoichiometric coefficient vector and $\bf{M}$ is a column vector of molecular weights. For simplicity, we use pure isotope molecular weights, and not the isotope-weighted molecular weights.

nu = [-1 -1 1 1];
M = [28; 18; 2; 44];
nu*M
ans =

     0

Atomic mass balances

For any balanced chemical equation, there are the same number of each kind of atom on each side of the equation. Since the mass of each atom is unchanged with reaction, that means the mass of all the species that are reactants must equal the mass of all the species that are products! Here we look at the n C O H

reactants = [-1 -2 -2]
products  = [ 1  2  2]
M = [12.011; 15.999; 1.0079]
reactants =

    -1    -2    -2


products =

     1     2     2


M =

   12.0110
   15.9990
    1.0079

Now if we add the mass of reactants and products, it should sum to zero (since we used the negative sign for stoichiometric coefficients of reactants).

products*M + reactants*M
ans =

     0

Summary

That's all there is to mass conservation with reactions. Nothing changes if there are lots of reactions, as long as each reaction is properly balanced, and none of them are nuclear reactions!

tags: reaction engineering

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